Integrand size = 28, antiderivative size = 297 \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^2} \, dx=\frac {\left (\frac {1}{16}+\frac {3 i}{16}\right ) d^{3/2} \arctan \left (1-\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} a^2 f}-\frac {\left (\frac {1}{16}+\frac {3 i}{16}\right ) d^{3/2} \arctan \left (1+\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} a^2 f}+\frac {\left (\frac {1}{32}-\frac {3 i}{32}\right ) d^{3/2} \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)-\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} a^2 f}-\frac {\left (\frac {1}{32}-\frac {3 i}{32}\right ) d^{3/2} \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)+\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} a^2 f}+\frac {3 d \sqrt {d \tan (e+f x)}}{8 a^2 f (1+i \tan (e+f x))}-\frac {d \sqrt {d \tan (e+f x)}}{4 f (a+i a \tan (e+f x))^2} \]
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Time = 0.53 (sec) , antiderivative size = 297, normalized size of antiderivative = 1.00, number of steps used = 12, number of rules used = 9, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.321, Rules used = {3639, 3677, 3615, 1182, 1176, 631, 210, 1179, 642} \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^2} \, dx=\frac {\left (\frac {1}{16}+\frac {3 i}{16}\right ) d^{3/2} \arctan \left (1-\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} a^2 f}-\frac {\left (\frac {1}{16}+\frac {3 i}{16}\right ) d^{3/2} \arctan \left (\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}+1\right )}{\sqrt {2} a^2 f}+\frac {\left (\frac {1}{32}-\frac {3 i}{32}\right ) d^{3/2} \log \left (\sqrt {d} \tan (e+f x)-\sqrt {2} \sqrt {d \tan (e+f x)}+\sqrt {d}\right )}{\sqrt {2} a^2 f}-\frac {\left (\frac {1}{32}-\frac {3 i}{32}\right ) d^{3/2} \log \left (\sqrt {d} \tan (e+f x)+\sqrt {2} \sqrt {d \tan (e+f x)}+\sqrt {d}\right )}{\sqrt {2} a^2 f}+\frac {3 d \sqrt {d \tan (e+f x)}}{8 a^2 f (1+i \tan (e+f x))}-\frac {d \sqrt {d \tan (e+f x)}}{4 f (a+i a \tan (e+f x))^2} \]
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Rule 210
Rule 631
Rule 642
Rule 1176
Rule 1179
Rule 1182
Rule 3615
Rule 3639
Rule 3677
Rubi steps \begin{align*} \text {integral}& = -\frac {d \sqrt {d \tan (e+f x)}}{4 f (a+i a \tan (e+f x))^2}-\frac {\int \frac {-\frac {a d^2}{2}+\frac {5}{2} i a d^2 \tan (e+f x)}{\sqrt {d \tan (e+f x)} (a+i a \tan (e+f x))} \, dx}{4 a^2} \\ & = \frac {3 d \sqrt {d \tan (e+f x)}}{8 a^2 f (1+i \tan (e+f x))}-\frac {d \sqrt {d \tan (e+f x)}}{4 f (a+i a \tan (e+f x))^2}-\frac {\int \frac {\frac {a^2 d^3}{2}+\frac {3}{2} i a^2 d^3 \tan (e+f x)}{\sqrt {d \tan (e+f x)}} \, dx}{8 a^4 d} \\ & = \frac {3 d \sqrt {d \tan (e+f x)}}{8 a^2 f (1+i \tan (e+f x))}-\frac {d \sqrt {d \tan (e+f x)}}{4 f (a+i a \tan (e+f x))^2}-\frac {\text {Subst}\left (\int \frac {\frac {a^2 d^4}{2}+\frac {3}{2} i a^2 d^3 x^2}{d^2+x^4} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{4 a^4 d f} \\ & = \frac {3 d \sqrt {d \tan (e+f x)}}{8 a^2 f (1+i \tan (e+f x))}-\frac {d \sqrt {d \tan (e+f x)}}{4 f (a+i a \tan (e+f x))^2}-\frac {\left (\left (\frac {1}{16}-\frac {3 i}{16}\right ) d^2\right ) \text {Subst}\left (\int \frac {d-x^2}{d^2+x^4} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{a^2 f}-\frac {\left (\left (\frac {1}{16}+\frac {3 i}{16}\right ) d^2\right ) \text {Subst}\left (\int \frac {d+x^2}{d^2+x^4} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{a^2 f} \\ & = \frac {3 d \sqrt {d \tan (e+f x)}}{8 a^2 f (1+i \tan (e+f x))}-\frac {d \sqrt {d \tan (e+f x)}}{4 f (a+i a \tan (e+f x))^2}--\frac {\left (\left (\frac {1}{32}-\frac {3 i}{32}\right ) d^{3/2}\right ) \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {d}+2 x}{-d-\sqrt {2} \sqrt {d} x-x^2} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{\sqrt {2} a^2 f}--\frac {\left (\left (\frac {1}{32}-\frac {3 i}{32}\right ) d^{3/2}\right ) \text {Subst}\left (\int \frac {\sqrt {2} \sqrt {d}-2 x}{-d+\sqrt {2} \sqrt {d} x-x^2} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{\sqrt {2} a^2 f}-\frac {\left (\left (\frac {1}{32}+\frac {3 i}{32}\right ) d^2\right ) \text {Subst}\left (\int \frac {1}{d-\sqrt {2} \sqrt {d} x+x^2} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{a^2 f}-\frac {\left (\left (\frac {1}{32}+\frac {3 i}{32}\right ) d^2\right ) \text {Subst}\left (\int \frac {1}{d+\sqrt {2} \sqrt {d} x+x^2} \, dx,x,\sqrt {d \tan (e+f x)}\right )}{a^2 f} \\ & = \frac {\left (\frac {1}{32}-\frac {3 i}{32}\right ) d^{3/2} \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)-\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} a^2 f}-\frac {\left (\frac {1}{32}-\frac {3 i}{32}\right ) d^{3/2} \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)+\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} a^2 f}+\frac {3 d \sqrt {d \tan (e+f x)}}{8 a^2 f (1+i \tan (e+f x))}-\frac {d \sqrt {d \tan (e+f x)}}{4 f (a+i a \tan (e+f x))^2}--\frac {\left (\left (\frac {1}{16}+\frac {3 i}{16}\right ) d^{3/2}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} a^2 f}-\frac {\left (\left (\frac {1}{16}+\frac {3 i}{16}\right ) d^{3/2}\right ) \text {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} a^2 f} \\ & = \frac {\left (\frac {1}{16}+\frac {3 i}{16}\right ) d^{3/2} \arctan \left (1-\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} a^2 f}-\frac {\left (\frac {1}{16}+\frac {3 i}{16}\right ) d^{3/2} \arctan \left (1+\frac {\sqrt {2} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right )}{\sqrt {2} a^2 f}+\frac {\left (\frac {1}{32}-\frac {3 i}{32}\right ) d^{3/2} \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)-\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} a^2 f}-\frac {\left (\frac {1}{32}-\frac {3 i}{32}\right ) d^{3/2} \log \left (\sqrt {d}+\sqrt {d} \tan (e+f x)+\sqrt {2} \sqrt {d \tan (e+f x)}\right )}{\sqrt {2} a^2 f}+\frac {3 d \sqrt {d \tan (e+f x)}}{8 a^2 f (1+i \tan (e+f x))}-\frac {d \sqrt {d \tan (e+f x)}}{4 f (a+i a \tan (e+f x))^2} \\ \end{align*}
Time = 1.10 (sec) , antiderivative size = 181, normalized size of antiderivative = 0.61 \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^2} \, dx=-\frac {d \sec ^2(e+f x) \left (4 \sqrt [4]{-1} \sqrt {d} \arctan \left (\frac {(-1)^{3/4} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right ) (\cos (2 (e+f x))+i \sin (2 (e+f x)))-2 \sqrt [4]{-1} \sqrt {d} \text {arctanh}\left (\frac {(-1)^{3/4} \sqrt {d \tan (e+f x)}}{\sqrt {d}}\right ) (\cos (2 (e+f x))+i \sin (2 (e+f x)))+(1+\cos (2 (e+f x))+3 i \sin (2 (e+f x))) \sqrt {d \tan (e+f x)}\right )}{16 a^2 f (-i+\tan (e+f x))^2} \]
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Time = 0.81 (sec) , antiderivative size = 118, normalized size of antiderivative = 0.40
method | result | size |
derivativedivides | \(\frac {2 d^{3} \left (-\frac {\frac {-\frac {3 i \left (d \tan \left (f x +e \right )\right )^{\frac {3}{2}}}{2}-\frac {d \sqrt {d \tan \left (f x +e \right )}}{2}}{\left (i d \tan \left (f x +e \right )+d \right )^{2}}+\frac {i \arctan \left (\frac {\sqrt {d \tan \left (f x +e \right )}}{\sqrt {-i d}}\right )}{2 \sqrt {-i d}}}{8 d}-\frac {i \arctan \left (\frac {\sqrt {d \tan \left (f x +e \right )}}{\sqrt {i d}}\right )}{8 d \sqrt {i d}}\right )}{f \,a^{2}}\) | \(118\) |
default | \(\frac {2 d^{3} \left (-\frac {\frac {-\frac {3 i \left (d \tan \left (f x +e \right )\right )^{\frac {3}{2}}}{2}-\frac {d \sqrt {d \tan \left (f x +e \right )}}{2}}{\left (i d \tan \left (f x +e \right )+d \right )^{2}}+\frac {i \arctan \left (\frac {\sqrt {d \tan \left (f x +e \right )}}{\sqrt {-i d}}\right )}{2 \sqrt {-i d}}}{8 d}-\frac {i \arctan \left (\frac {\sqrt {d \tan \left (f x +e \right )}}{\sqrt {i d}}\right )}{8 d \sqrt {i d}}\right )}{f \,a^{2}}\) | \(118\) |
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Both result and optimal contain complex but leaf count of result is larger than twice the leaf count of optimal. 566 vs. \(2 (217) = 434\).
Time = 0.25 (sec) , antiderivative size = 566, normalized size of antiderivative = 1.91 \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^2} \, dx=\frac {{\left (4 \, a^{2} f \sqrt {-\frac {i \, d^{3}}{16 \, a^{4} f^{2}}} e^{\left (4 i \, f x + 4 i \, e\right )} \log \left (-\frac {2 \, {\left (i \, d^{2} e^{\left (2 i \, f x + 2 i \, e\right )} + 4 \, {\left (a^{2} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{2} f\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {-\frac {i \, d^{3}}{16 \, a^{4} f^{2}}}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{d}\right ) - 4 \, a^{2} f \sqrt {-\frac {i \, d^{3}}{16 \, a^{4} f^{2}}} e^{\left (4 i \, f x + 4 i \, e\right )} \log \left (-\frac {2 \, {\left (i \, d^{2} e^{\left (2 i \, f x + 2 i \, e\right )} - 4 \, {\left (a^{2} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{2} f\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {-\frac {i \, d^{3}}{16 \, a^{4} f^{2}}}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{d}\right ) + 4 \, a^{2} f \sqrt {\frac {i \, d^{3}}{64 \, a^{4} f^{2}}} e^{\left (4 i \, f x + 4 i \, e\right )} \log \left (\frac {{\left (i \, d^{2} + 8 \, {\left (a^{2} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{2} f\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {\frac {i \, d^{3}}{64 \, a^{4} f^{2}}}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{8 \, a^{2} f}\right ) - 4 \, a^{2} f \sqrt {\frac {i \, d^{3}}{64 \, a^{4} f^{2}}} e^{\left (4 i \, f x + 4 i \, e\right )} \log \left (\frac {{\left (i \, d^{2} - 8 \, {\left (a^{2} f e^{\left (2 i \, f x + 2 i \, e\right )} + a^{2} f\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}} \sqrt {\frac {i \, d^{3}}{64 \, a^{4} f^{2}}}\right )} e^{\left (-2 i \, f x - 2 i \, e\right )}}{8 \, a^{2} f}\right ) + {\left (2 \, d e^{\left (4 i \, f x + 4 i \, e\right )} + d e^{\left (2 i \, f x + 2 i \, e\right )} - d\right )} \sqrt {\frac {-i \, d e^{\left (2 i \, f x + 2 i \, e\right )} + i \, d}{e^{\left (2 i \, f x + 2 i \, e\right )} + 1}}\right )} e^{\left (-4 i \, f x - 4 i \, e\right )}}{16 \, a^{2} f} \]
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\[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^2} \, dx=- \frac {\int \frac {\left (d \tan {\left (e + f x \right )}\right )^{\frac {3}{2}}}{\tan ^{2}{\left (e + f x \right )} - 2 i \tan {\left (e + f x \right )} - 1}\, dx}{a^{2}} \]
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Exception generated. \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^2} \, dx=\text {Exception raised: RuntimeError} \]
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none
Time = 0.61 (sec) , antiderivative size = 198, normalized size of antiderivative = 0.67 \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^2} \, dx=-\frac {1}{8} \, d^{3} {\left (\frac {2 i \, \sqrt {2} \arctan \left (\frac {8 \, \sqrt {d^{2}} \sqrt {d \tan \left (f x + e\right )}}{4 i \, \sqrt {2} d^{\frac {3}{2}} + 4 \, \sqrt {2} \sqrt {d^{2}} \sqrt {d}}\right )}{a^{2} d^{\frac {3}{2}} f {\left (\frac {i \, d}{\sqrt {d^{2}}} + 1\right )}} + \frac {i \, \sqrt {2} \arctan \left (\frac {8 \, \sqrt {d^{2}} \sqrt {d \tan \left (f x + e\right )}}{-4 i \, \sqrt {2} d^{\frac {3}{2}} + 4 \, \sqrt {2} \sqrt {d^{2}} \sqrt {d}}\right )}{a^{2} d^{\frac {3}{2}} f {\left (-\frac {i \, d}{\sqrt {d^{2}}} + 1\right )}} + \frac {3 i \, \sqrt {d \tan \left (f x + e\right )} d \tan \left (f x + e\right ) + \sqrt {d \tan \left (f x + e\right )} d}{{\left (d \tan \left (f x + e\right ) - i \, d\right )}^{2} a^{2} d f}\right )} \]
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Time = 6.46 (sec) , antiderivative size = 179, normalized size of antiderivative = 0.60 \[ \int \frac {(d \tan (e+f x))^{3/2}}{(a+i a \tan (e+f x))^2} \, dx=\frac {\frac {d^3\,\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}}{8\,a^2\,f}+\frac {d^2\,{\left (d\,\mathrm {tan}\left (e+f\,x\right )\right )}^{3/2}\,3{}\mathrm {i}}{8\,a^2\,f}}{-d^2\,{\mathrm {tan}\left (e+f\,x\right )}^2+d^2\,\mathrm {tan}\left (e+f\,x\right )\,2{}\mathrm {i}+d^2}-\mathrm {atan}\left (\frac {8\,a^2\,f\,\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}\,\sqrt {-\frac {d^3\,1{}\mathrm {i}}{64\,a^4\,f^2}}}{d^2}\right )\,\sqrt {-\frac {d^3\,1{}\mathrm {i}}{64\,a^4\,f^2}}\,2{}\mathrm {i}-\mathrm {atan}\left (\frac {16\,a^2\,f\,\sqrt {d\,\mathrm {tan}\left (e+f\,x\right )}\,\sqrt {\frac {d^3\,1{}\mathrm {i}}{256\,a^4\,f^2}}}{d^2}\right )\,\sqrt {\frac {d^3\,1{}\mathrm {i}}{256\,a^4\,f^2}}\,2{}\mathrm {i} \]
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